how would you do this:
Find the values of x for which f(x)=g(x)
1. F(x)=x^2, g(x)=x+2
2007-01-19 13:36:19 · 4 answers · asked by Scooter 1 in Science & Mathematics ➔ Mathematics
f(x) = g(x)
x² = x + 2
x² - x - 2 = 0
(x - 2)(x + 1) = 0
x = 2 or -1
Check:
(2)² = 2 + 2, check
(-1)² = -1 + 2, check
2007-01-19 13:39:09 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
F(x) = G(x)
0 = F(x) - F(x)
0 = x^2 - (x+2) = x^2 - x - 2
0 = (x - 2)(x + 1)
Roots (zero's)
x = 2 and x = -1
2007-01-19 21:43:20 · answer #2 · answered by lostlatinlover 3 · 0⤊ 0⤋
x^2=x+2 so x^2-x-2=0 2nd degree equ. so
x= (1+-Sqrt(1+8))/2 = (1+-3)2 x=2 x=-1
2007-01-20 07:41:44 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
x^2 = x + 2
x^2 - x - 2 = 0
(x-2)(x+1) = 0
x = 2 x = -1
Bozo
2007-01-19 21:39:45 · answer #4 · answered by bozo 4 · 0⤊ 0⤋