Place over a common denominator, in this case 19*28 = 532. The fractions then become (3x19)/532 and (4*28)/532 which are 57/532 and 112/532; now you can tell which is larger.
2007-01-19 12:38:36
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answer #1
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answered by gp4rts 7
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Well Catherine, you should know that it's not '='
To determine which is greater, find the lowest common denominator. In this case, it's just easier to 'cross multiply' : 19*3 and 28* 4
So...
3/28 = (3*19)/(28*19) = 57/(28*19)
4/19 = (4*28)/(28/19) = 112/(28*19)
Since the denominators are now equal, just compare the numerators: 112 is greater than 57, therefore
3/28 < 4/19
By the way...
Another way to do this is by ESTIMATION:
3/28 is close to 3/30, which is just .1
4/19 is close to 4/20, which is just .2
You KNOW that .2 is bigger than .1, so 3/28 < 4/19
2007-01-19 20:42:45
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answer #2
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answered by mjatthebeeb 3
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( 3 / 28 ) ? ( 4 / 19 )
( 3 / 28 ) * ( 19 / 19 ) ? ( 4 / 19 ) * (28 / 28 )
- Because you can multiply either side of any equation by 1 without changing the equation.
( 3 * 19 ) / ( 28 * 19 ) ? ( 4 * 28 ) / ( 19 * 28 )
- Now you can compare the fractions because the denominators are the same.
( 57 ) / (28 * 19 ) ? ( 112 ) / ( 19 * 28 )
( 57 / 532 ) < ( 112 / 532 )
2007-01-19 20:39:58
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answer #3
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answered by themountainviewguy 4
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It's easiest to compare two fractions when their denominators are the same. So multiply the left side by 19/19 and the right side by 28/28 to get both denominators the same:
(3/28)*(19/19) ? (4/19)*(28/28)
(3*19)/(28*19) ? (4*28)/(28*19)
57/532 ? 112/532
Now that the denominators are the same, just compare the numerators. Obviously, fifty-seven 532nds is less than one hundred and twelve 532nds. So 3/28 must be LESS THAN 4/19.
2007-01-19 20:40:03
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answer #4
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answered by Anonymous
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What relationship is "?" - ">", "<" or "="?
3/28 ? 4/19
By procedure:
(Always appropriate)
Multiplying both sides by 28, a positive number, preserves the relationship.
3 ? 4*28/19
3 ? 112/19
Multiplying both sides by 19, a positive number, preserves the relationship.
3*19 ? 112
51 ? 112
So the relationship is <.
By quick observation:
(Not always appropriate)
Notice 3 < 4 and 28 > 19.
i.e. 3 < 4 and 1/28 < 1/19. (Taking reciprocal reverses a sign.)
So multiplying those two "<" inequalities gives another "<" inequality.
3/28 < 4/19
2007-01-19 21:00:18
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answer #5
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answered by Anonymous
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With experience, it is easy to tell that
3/28<4/19 the right side has a bigger numerator & smaller denominator, so it is larger. In general, you cant do that.
most direct is to find LCD.
3/28=(3*19)/(28*19)=57/532
4/19-(4*28)/(19*28)=112/532
57/532<112/532 so
3/28<4/19
2007-01-19 21:30:03
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answer #6
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answered by yupchagee 7
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3/28 = 57/532
4/19 = 76/532
so
57/532 < 76/532
or
3/28 < 4/19
2007-01-19 20:42:20
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answer #7
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answered by Amy B 2
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3/28=.107143
4/19=.210526
I found these answers by dividing!
3/28<4/19
I hope this helps!
2007-01-19 22:57:15
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answer #8
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answered by Anonymous
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another option is to turn it into a decimal. Divide the top number by the bottom number.
3/28= 0.107
4/19= 0.211 so 4/19 is greater than 3/28
good luck
2007-01-19 20:42:30
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answer #9
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answered by Should be Working! 4
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(3/28)x(19/19)=57/532
(4/19)x(28/28)=112/532.
decide yourself what sign to insert
2007-01-19 20:49:18
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answer #10
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answered by charlatan 7
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