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2007-01-19 10:37:24 · 5 answers · asked by stefanie n 1 in Science & Mathematics Mathematics

5 answers

log2 (2^(-5))= -5

Done!

2007-01-19 10:42:07 · answer #1 · answered by Jerry P 6 · 1 0

log2(1/32). Perhaps 2 is the base of log.
If it is so,
then log (1/32) = log (2^-5)= - 5 log 2 = -5 Answer
The base of logs every where is 2, though we have not explicitly written.

2007-01-19 10:50:41 · answer #2 · answered by Anonymous · 1 0

log2(1/32)=log2[(2)^(-5)]= - 5*log2(2)= - 5*1= - 5

2007-01-19 10:43:18 · answer #3 · answered by battousai 1 · 1 0

Answer is -5

2007-01-19 10:41:04 · answer #4 · answered by Anonymous · 0 0

log(2)(1/32)
(log(1/32))/(log(2))
(log(32^-1))/(log(2))
-(log(32))/log(2)
ANS : -5

2007-01-19 10:53:09 · answer #5 · answered by Sherman81 6 · 1 0

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