Write the logarithm equation ln(2) = .693 as an equation about exponents.?

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2007-01-19 10:20:32 · 4 answers · asked by haileybaby331 1 in Science & Mathematics ➔ Mathematics

e^(0.693) = 2

2007-01-19 10:24:12 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋

ln is log base e

log[e]2= .693

e^.693=2

2007-01-19 10:24:47 · answer #2 · answered by 7 · 0⤊ 0⤋

Maybe this way?...

e^(x)=2

Taking ln in boht sides:

x=ln(2)=0.693

I hope I helped you.

Bye!

2007-01-19 10:35:18 · answer #3 · answered by nicolaspeye 1 · 0⤊ 0⤋

e^(0.693) = 2

2007-01-19 10:36:10 · answer #4 · answered by ENA 2 · 0⤊ 0⤋