Help me with this hard math problem please to study for math team!?

Question

If x= -2, find the value of x-2x(squared) -(2x)(squared).

Answer 1

x-2x^2-(2x)^2

x=-2
-2-2(-2)^2-(2*-2)^2
parenthesis first
-2-2(-2)^2-(-4)^2
now exponents
-2-2*4-16
now multiplication
-2-8-16
now add/subtract
-26

answer is -26

Answer 2

Solve: x - 2x^2 - 2x^2 when x = - 2

First: the problem gives you the value/number for the x-variable...

Sec: replace -2 with the x-variable in the expression...

(-2) - 2(-2)^2 - 2(-2)^2

Third: solve the expression according to order of operations >>
>> ( ), exponents, multiplication, division, addition & subtraction...

(-2) - 2(4) - 2(4)

- 2 - 8 - 8

-10 - 8

- 18

P.S. Other individuals who responded: if you found the solution to be 18-you're correct.

Answer 3

I assume you mean x - 2x^2 - (2x)^2 where ^ means raised to the power.

Then, substituting:

(-2) - 2(-2)^2 - (2(-2))^2
= -2 - 2(4) - (-4)^2
= -2 - 8 - 16
= -26. All done.

Answer 4

Plug in -2 for each X you see, so....

-2 - 2(-2)squared- 2(-2)squared

Do the exponent portion first, then multiply, then subract

I believe the answer is 30, but check to make sure!

Answer 5

I solved it like this:
x - 2x² -(2x)²
-2 -2.4 -(-4)²
-2 -8 -16
-26

Answer 6

Oh, gee, I'm not sure, but I think the answer is -18 (that's negative 18).

Answer 7

-18

Answer 8

-18

Answer 9

Hi. Just plug in the value for x. -2-(-2 x-2) - (-2 x -2), or -2 -(4) - (4).

I'd call that -10

OK, OK, so I misinterpreted. Check the other answers. Sorry.

Answer 10

x-2x^2-(2x)^2
-2-(2)(-2)^2-2(-2)^2
-2-(2)(4)-2(4)
-2-8-8
= -18