2007-01-19 09:52:32 · 12 answers · asked by Anonymous in Sports ➔ Football (American)
Well, the TEXANS have never lost in the playoffs...LOL!!!
2007-01-19 10:25:44 · answer #1 · answered by askareferee 2 · 0⤊ 0⤋
Actually, a 2-0 record is not superior to an 11-2 record. Percentage-wise yes, but in a "standings" format, an 11-2 team would be 3.5 games higher in the standings. By the way, Dallas has 32 total playoff wins, the highest in the NFL.
2007-01-19 18:10:47 · answer #2 · answered by zonhambulo 2 · 0⤊ 0⤋
Depending what you want to use for games played. There are some team with only a few playoff games and a good winning %. If you go with a team 40 or more playoff games, I think it is the Pats with a 19 - 11 record.
2007-01-19 21:44:22 · answer #3 · answered by Billy Jack H 1 · 0⤊ 0⤋
Carolina Panthers
http://superbowl.com/playoffs/history/standings
2007-01-19 18:10:43 · answer #4 · answered by BAGOFSWAGS 5 · 0⤊ 0⤋
Heh it could be Detroit....they were good back in the 30s, winning a few NFL championships in the pre-Super Bowl era. Since then, they've only BEEN to the playoffs once and lost, so they probably dont have many postseasons losses on their record :)
2007-01-19 18:11:12 · answer #5 · answered by droid327 5 · 0⤊ 0⤋
Wierd question cause, a 2-0 record is better than a 11-2 record mathematically, a better question might be who has more playoff wins
2007-01-19 18:01:41 · answer #6 · answered by Anonymous · 0⤊ 0⤋
The San Fransisco 49ers
2007-01-19 23:38:03 · answer #7 · answered by gjkm16751 1 · 0⤊ 0⤋
i know a few years ago, the panthers of carolina had the best record percentage-wise, but with the loss to seattle in the NFC championship in the 2005-2006 playoffs, they may not be the best now, im not 100 percent
2007-01-19 18:21:59 · answer #8 · answered by skittleville 1 · 0⤊ 0⤋
Pittsburgh Steelers
2007-01-20 14:53:34 · answer #9 · answered by Jake 1 · 1⤊ 0⤋
Dallas Cowboys 32-23 .582 has it in wins.
Carolina Panthers 6-3 .667 has it in percentage.
2007-01-20 00:54:31 · answer #10 · answered by Imaginary Friend 4 · 0⤊ 0⤋