Just a little math homework!
2007-01-19 09:50:02 · 9 answers · asked by Adriane 2 in Science & Mathematics ➔ Mathematics
Factors the Polynomial:
4y^8-25x^2 =(2y^4)^2 - (5x)^2
= (2y^4 + 5x) (2y^4 - 5x) Answer.
2007-01-19 09:57:18 · answer #1 · answered by Anonymous · 1⤊ 1⤋
First you could take out y^6 from each and each. y^6 (4y^2 + 36y + 80 one) At this aspect the factoring looks lots less demanding than previously so (2y + 9)(2y +9) = 4y^2 + 18y + 18y + 80 one (you in reality ought to wager factors of four and 80 one, 2 and 9 got here about to artwork properly) the only ideal answer is y^6(2y+9)^2
2016-11-25 21:05:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4y^8 - 25x^2 = (2y^4 - 5x)(2y^4 + 5x)
2007-01-19 11:05:34 · answer #3 · answered by Sherman81 6 · 1⤊ 1⤋
(2y⁴ - 5x) × (2y⁴ + 5x)
Then technically you could keep going.... Your teacher probably wouldn't want you to but, you could do:
(√2y² - √(5x)) × (√2y² + √(5x)) × (√2y² - i√(5x)) × (√2y² + i√(5x))
and then even farther....
(⁴√2y - ⁴√(5x)) ×
(⁴√2y + ⁴√(5x)) ×
(⁴√2y - i⁴√(5x)) ×
(⁴√2y + i⁴√(5x)) ×
(⁴√2y - (√2/2 + √2/2i)⁴√(5x)) ×
(⁴√2y + (√2/2 + √2/2i)⁴√(5x)) ×
(⁴√2y - (-√2/2 + √2/2i)⁴√(5x)) ×
(⁴√2y + (-√2/2 + √2/2i)⁴√(5x))
But I think you should stick with the top answer.
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Koalahash: Start menu, Run..., type in cmap and hit enter.
2007-01-19 09:54:01 · answer #4 · answered by Jim Burnell 6 · 1⤊ 1⤋
(2y^4 + 5x) (2y^4 - 5x)
2007-01-20 11:01:48 · answer #5 · answered by nicecutestpooky 1 · 0⤊ 1⤋
(2y^4 + 5x) (2y^4 - 5x)
2007-01-19 09:53:01 · answer #6 · answered by cutest pooky 3 · 1⤊ 1⤋
(2y^4+5x)(2y^4-5x)
2007-01-19 11:11:49 · answer #7 · answered by Anonymous · 1⤊ 1⤋
(2y^4+5x)(2y^4-5x)
2007-01-19 10:04:28 · answer #8 · answered by Bill F 6 · 1⤊ 1⤋
hey jim burness, how did you get all those mathematical symbols in your answer? that's huge!
2007-01-19 10:03:52 · answer #9 · answered by koalahash 3 · 1⤊ 1⤋