I cannot find any way to solve this and am in some desperate need of help. Anyone?
One particle has a mass of 3.00x10^-3 kg and a charge of +7.80 µC. A second particle has a mass of 6.00x10^-3 kg and the same charge. The two particles are initially held in place and then released. The particles fly apart, and when the separation between them is 0.100 m, the speed of the 3.00x10^-3 kg particle is 125 m/s. Find the initial separation between the particles.
2007-01-19 09:22:02 · 2 answers · asked by larkinfan11 3 in Science & Mathematics ➔ Physics
I originally thought to solve it using the electrostatic force between the two charges and getting the acceleration - but this proved arduous.
Always sketch a diagram of the two states and put on any given values. This will help you see what is going on!
(NOTE: You will ALSO need to use the conservation of momentum to get the speed of the second particle (which I think will be 62.5m/s)).
The best way is to use the conservation of energy in the form:
Total Energy at Start = Total Energy at End.
At Start:
We have only Potential Energy due to the charge Repulsion - and it is this term which contains our unknown.
At End
We have two terms: the potential energy due to the charge; and the kinetic energy of the particles.
The Equation can then be solved for the unknown.
CopyLeft:RC
2007-01-19 10:24:51 · answer #1 · answered by Rufus Cat 4 · 0⤊ 0⤋
Try asking any divorced couples
2007-01-19 18:21:34 · answer #2 · answered by Dosage 3 · 0⤊ 1⤋