calculus question?

0 ⤊

find the indefinite integral

the integral of (x+1)e^(x^2+2x)

2007-01-19 08:50:59 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

Integrate (x + 1)e^(x² + 2x)dx

Let
u = e^(x² + 2x)
du = (2x + 2)e^(x² + 2x)dx
du/2 = (x + 1)e^(x² + 2x)dx

∫(x + 1)e^(x² + 2x)dx = ∫(du/2) = u/2 + C = e^(x² + 2x)/2 + C

2007-01-19 09:10:10 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋

(x+1)e^(x^2+2x)
using u substitution, as u=x^2+2x, then du=(2x+2)dx
gives:
(1/2)du e^u
integral of e^u is e^u so,
integral = (1/2)e^u + c
= (1/2)e^(x^2+2x) + C

2007-01-19 17:02:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋

is it (1/2) e^(xÂ²+2x) + C ?

2007-01-19 16:55:37 · answer #3 · answered by bequalming 5 · 0⤊ 1⤋

1/2*e^(x*x+2))+C

j

2007-01-19 16:55:14 · answer #4 · answered by odu83 7 · 0⤊ 1⤋