3-5/2x-3x^2=0?

Question

math question

Answer 1

If memory serves me right, you can multiply all three terms by "2" to clear the fraction. That gives you
(2)3 - (2)5/2x - (2)3x^2=0
6-5x-6x^2=0

I re-arrange the equation to the proper format
-6x^2 - 5x + 6 =0
Factoring that equation into
(-3x + 2)(2x + 3) = 0
solving each expression
-3x + 2 = 0
-3x = -2
x = 2/3
and
2x + 3 = 0
2x = -3
x = -3/2

Answer 2

3 - (5/2)x - 3x^2 = 0
6 - 5x - 6x^2 = 0

(3+2x)(2-3x)=0

Two solutions are 3=-2x; 2=3x

x={-1.5, 0.67}

Answer 3

Remember your quadratic equation ?

x=-b+-the square root of b^2-4ac all over 2a (tried to write it below) (remember...b^2-4ac is ALL under the radical [square root symbol]). Where, a=-3, b=-5/2, and c=3...just plug in the numbers and solve for x. Remember though...you will have TWO answers...one is usually positive, and one is usually negative. The "plus" and "minus" signs mean you have to do the formula TWICE...one as a "plus" and once as a "minus".

-b±√b²-4ac
2a