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put these in simplest form.

Question 1. 5x - 3/x

a. 5x-3/x
b. 5x^2 - 3/x
c. 4x/3
d. 2/x

Question 2. x/x+1 - x+1/ x + 2

Question 3. (2x + 3/x) (x-2/x)

Question 4. (9-1/x^2) divided by (3x-1)

2007-01-19 08:42:39 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

no 1. answer =b

no.2 answer= 6x + 4 or 2(3x +2)

no.3 answer = x^3 +5

no. 4 answer : 24x - 8 = x^2
Tell me if u need me to explain how i got the answers.

2007-01-19 08:54:46 · answer #1 · answered by sweetums 3 · 0 0

answers 1
a. 5x^2-3
b. 5x^3-3
c. its alredy on its simplest form, u could try 0.75x though
d. its alredy on its simplest form, u could try 2(x^-1)

answers 2

[x^2-(x+1)^2+2x(x+1)] / x(x+1)

answers 3

2x^2+6/x^2+7

answers 4

8 / [x^2(3x-1)]


remember these are not equations, but members you want to reduce. You cant equal them to 0



hopefully ill be useful. regards nexus

2007-01-19 17:02:46 · answer #2 · answered by nexusdhr84 2 · 0 0

1.)
5x-3x
They are like terms, so just subtract and keep the x
Answer is 2x
D


3.) 2x + 3x = 5x
X - 2/x = -x
-x multiplied by 5x is -5x2 (x squared)

2007-01-19 16:49:37 · answer #3 · answered by Anonymous · 1 0

I am a Junior High Pre-Algebra teacher and I must say that it would be best to get help from a tutor as to HOW to do it or research examples in your math book.

Getting the answers is not going to help in the long run. You need to learn how to not just a quick fix.

2007-01-19 16:49:31 · answer #4 · answered by April 1 · 0 2

You have good manners. Now, try to learn how to solve this on your own or you'll have a harder time later. Ask for tutoring at school. Sorry to give you advice instead of answers but I don't know how to do the problems (that's why I'm giving you this advice)

2007-01-19 16:47:02 · answer #5 · answered by Anonymous · 0 2

It is Friday so I am not doing math! I will tell you what my mom told me yesterday:
LOOK IT UP!!!

2007-01-19 16:46:22 · answer #6 · answered by Im Casey, Baby! 1 · 1 1

do ya own homework

2007-01-19 16:45:45 · answer #7 · answered by Anonymous · 1 2

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