Find the center of the hyperbola (1/10)(x-1)^2-(y-1)^2=1.?

Answer 1

(1/10)(x - 1)^2 - (y - 1)^2 = 1
(((x - 1)^2)/10) - (y - 1)^2 = 1

In the formula

(((x - h)^2)/a^2) - (((y - k)^2)/b^2) = 1

(h,k) is the center

ANS : (1,1)

Answer 2

The center is simply how far from the origin it is displaced.

You find this by taking (x-x0) and (y-y0)

since x0 and y0 are both -1, your center is

(1,1)