Find the two asymptotes for the hyperbola (1/10)(x-1)^2-(y-1)^2=1.?

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2007-01-19 07:43:16 · 3 answers · asked by don v 1 in Science & Mathematics ➔ Mathematics

I was told there would be no math on this test.

2007-01-19 07:47:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋

(1/10)(x-1)^2-(y-1)^2=1

The asymptotes are y = +/- bx/a
So y= (sqrt(10)/10)x and
y = - (sqrt(10)/10)x

2007-01-19 15:55:47 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

y=positive and negative radical 10 x

2007-01-19 15:48:38 · answer #3 · answered by rubydragon 2 · 0⤊ 0⤋