The base of a ladder is 10 ft away from the wall. The top of the ladder is 11 feet from the floor. Find the length of the ladder to the nearest thousandth
2007-01-19 07:37:10 · 5 answers · asked by CookFrNW 3 in Science & Mathematics ➔ Mathematics
Pythagorean theorem. We assume the wall forms a right angle, so you have two legs of the right triangle being 10 and 11.
a² + b² = c²
10² + 11² = c²
100 + 121 = c²
c² = 221
c = sqrt(221)
c ≈ 14.8660687...
Rounding to the nearest thousandth:
c ≈ 14.866 ft.
The ladder is approximately 14.866 feet long. (That's around 14 feet 10 13/32 inches long).
2007-01-19 07:42:01 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋
The ladder and the wall form a triangle. You know the base and altitude of the triangle, you need to find the hypotenuse. Use the formula a^2 + b^2 = c^2 where a is the altitude and b is the base.
11^2 + 10^2 = c^2
121 + 100 = c^2, now take the square root of each side
c = square root of 221
c = 14.86606875 ft.
to the nearest thousandth...
14.866 ft.
2007-01-19 15:45:55 · answer #2 · answered by Rockit 5 · 1⤊ 0⤋
you'll have to use Pythagorean theorem where c i the the hypotenuse of a right angled triangle and the other two sides are a and b.
Imagine that the ladder is slanting against the wall.this makes a right triangle with the legth of the triangle as hypotenuse and the wall as one side(say a)and the ground as the other side(say b)
c=sqrt(a2+b2)
= sqrt(11^2+10^2)
= sqrt(121+100)
= sqrt(221)
=14.866
2007-01-19 15:52:38 · answer #3 · answered by purpleraiment 2 · 1⤊ 0⤋
Use Pythagorean theorem
l = sqrt(10^2 + 11^2) =sqrt(221) = 14.866
2007-01-19 15:43:25 · answer #4 · answered by ironduke8159 7 · 1⤊ 0⤋
I believe that I've come to the conclusion that the Answer is 14.866 feet.
2007-01-19 16:02:19 · answer #5 · answered by crsport24 3 · 0⤊ 0⤋