English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I am having trouble understanding the concept of this. Can anyone help me?
To test the quality of it's paper clps , a manufacture randomly collects 100 paper clips from each batch. After 10 random samples, the following results are obtained.

Sample A B C D E F G H I J
defective 2 1 2 0 1 2 1 4 2 3

A) What percentof the paper clips are defective in sample A?

B) What percent of the paper clips are defective in the total of samples A to J?

c) If the sample K is taken, how many defective paperclips might you expect? Select the best answer for each number.
6 : yes, no, maybe
3: yes, no, maybe
2: yes, no, maybe
0: yes, no, maybe

Any help in explaining this would be great. I can't get ahold of the math teacher and I want to finish this lesson. Haven't even gotten to the real questions yet !

2007-01-19 05:37:50 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

1. 2% of paper clips are defective in sample A. there are 100 paper clips in each sample, if 2 are defective, 2/100 = 0.02 or 2%

2. 1.8% of the paper clips are defective in A through J. 2+1+2+0+1+2+1+4+2+3 = 18, 100+100+100+100+100+100+100+100+100+100 = 1000, 18/1000 = 0.018 or 1.8%

3. since 2 is the closest to the average of 1.8% of the paper clips being defective, that would be the most likely number of paper clips defective.

2007-01-19 05:52:30 · answer #1 · answered by andrew b 3 · 0 0

A) There are 100 clips in sample A and 2 are defective. What's that percentage?

B) Add up the number of defectives and divide by total number, then convert decimal to percent

2007-01-19 05:50:32 · answer #2 · answered by modulo_function 7 · 0 0

A) 2 defective out of 100 = 2%
(just divide the number of defective by the total number)

B) 1.8%: add up the defective & divide by the total number, so:
(2+1+2+0+1+2+1+4+2+3)/1000 = 18/1000 = .018
which is equivalent to 1.8% (.018 = 1.8*100/100)

C) based on the average % which is 1.8, I would expect around 2 defective
so 6: no
3: no
2: yes
0: no

2007-01-19 05:49:46 · answer #3 · answered by MM 2 · 0 1

A. 2 out 100 is 2 percent.
B. 18 out of 1000 = 1.8 percent
Now based on that information, what is the most likely to occur in you 11th sample which is labeled K.
it would be 2

2007-01-19 05:50:01 · answer #4 · answered by James O only logical answer D 4 · 0 0

You look up the numbers you need, and to find the median, line all the numbers up in order, and start crossing the numbers off on each side until you get to the last one or 2 numbers. If there are 2, find the average of them by adding them together and divide them by 2. To find the mode, the most frequent number(s) you just find what numbers are the most in the set. For the average, you add all of the numbers up, and count how many numbers there were, and divide them by that number. Eg: to find the mean of 3, 5, and 6, you would add them all up and get 14, and then divide it by 3 because there are 3 numbers. Hope this helps

2016-05-23 21:56:39 · answer #5 · answered by Anonymous · 0 0

fedest.com, questions and answers