For the same circle x^2+y^2+2x-6y-6=0 of the two previous two questions, find the radius.?

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2007-01-19 04:55:47 · 4 answers · asked by pkbrauer 1 in Science & Mathematics ➔ Mathematics

(x^2 + 2x + 1) + (y^2 - 6y + 9) -10 - 6 = 0
(x+1)^2 + (y - 3)^2 = 16
the circle of center (-1,3) and radius 4

2007-01-19 05:19:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋

4

(x+1)^2 + (y-3)^2 = 16

2007-01-19 13:01:08 · answer #2 · answered by trichbopper 4 · 0⤊ 0⤋

tthe center is the point(-1,3) and the radius is sqrt(1+9+6) =4

2007-01-19 13:03:35 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋

I guess you need to know this:

Standard form for circle:

(x-h)Â²+(y-k)Â²=rÂ²

r = radius
center = (h,k)

2007-01-19 13:01:36 · answer #4 · answered by bequalming 5 · 0⤊ 0⤋