calculate the denstity of the shpere?

Question

how do you calculate this problem?

volume=4/3pi r3 use 3.14 for pi

diameter is 4.2 mass is 18.6

Answer 1

In the question, units of diameter and mass are not given I assume, these are cm and gram respectively and the sphere is solid and not hollow.
radius r= diameter /2 =2.1 cm
Volume V = (4pi/3) r^3
=(4 pi/3) (2.1)^3 cm^3
=38.79 cm^3
mass m=18.6 grams
density d = m/V = 18.6/ 38.79 =0.48 g/cm^3 Answer.

Answer 2

Density is defined as the mass divided by the volume. So first calculate the volume of the sphere using the equation you have. Then, divide the mass by the volume, and you've calculated the density.

Answer 3

Density = mass/volume

density=18.6/[4/3*3.14*2.1^3]

density=0.4797 mass unit/volume unit

Answer 4

Density is mass per unit volume

D = m / V

Answer 5

Density is mass/volume, so first step is to calculate volume.
r = 2.1

V = 4/3 * 3.14 * 2.1^3 = 38.77

18.6 / 38.77 = .48

Answer 6

shall we embody the sector as a stack of discs of a small yet equivalent top, smallest on backside, increasing in diameter to the middle, that's greatest, and lowering in length till smoothing out on precise. Does this visualisation make experience? word that the smaller in top the discs are, the greater gentle the "sphere" would be and the greater precise our quantity estimate would be while including the volumes of all the discs. all of us understand the quantity of a disc (a cylinder, incredibly) is the backside situations top, or ?r²h. do we be sure the radius of a particular disc reckoning on its place interior the stack? In my thoughts, we are stacking the discs vertically, so i'll locate the radius as a function of 'y'. a photograph facilitates terrific. The periphery of a sphere is, of path, formed like a circle. The equation of a circle is x² + y² = R². The radii correspond to 'x' and that i'm applying a capital 'R' for the radius of the sector itself, no longer the guy discs. So given a disc in any place 'y', the radius, 'x' is given by using: x = ?(R² - y²), i.e., r = ?(R² - y²). So given a disc in any place 'y', the quantity, 'v' is given by using: v = ? (?(R² - y²))² h, i.e., v = ? (R² - y²) h. Now, we are attempting to locate the volumes of *all* the discs and upload them at the same time. At this factor issues grow to be a splash messy, and because i understand we are going to be applying calculus to chop back the heights of all the discs subsequently increasing how many there are, i'll circulate at the instant to that. you may seek for suggestion out of your textbook on the gory information of the essential Theorem of Calculus. we are going to be comparing the quintessential of ? (R² - y²) dy from -R to R. ? S(R² - y²)dy ? S(R²)dy - ? S(y²)dy ? [year²] - ? [a million/3y³] evaluated from -R to R: ? [RR² - -RR²] - ? [a million/3R³ - a million/3(-R)³] ? [R³ + R³] - ? [2/3R³] ? (2R³ - 2/3R³) ?4/3R³ hi, that formula seems known! i think of we are achieved, confident i understand the formatting seems superb. be at liberty to e mail me for any clarifications.

Answer 7

diameter=4.2.....=> radius= 2.1

You calculate volume from the formula you have.

You can calculate density from the formula d=m/v