What is the range of y = 5(2)^x - 4?
Additional Details
12 minutes ago
is it:
*The set of positive real numbers greater than 0
*The set of positive real numbers greater than -4
*The set of positive real numbers greater than 1
*The set of positive real numbers greater than 4
2007-01-19 04:41:49 · 5 answers · asked by Asking Q 1 in Science & Mathematics ➔ Mathematics
Without Calculus, it's all about recognition when it comes to the range of exponential functions.
Let f(x) = a * (b^x) + k
The range of an exponential function in this form would be
(k, infinity).
In our case, k = -4, so the range is
(-4, infinity)
i.e. the set of real numbers greater than -4.
2007-01-19 04:48:00 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
Already answered this before. The function is asymptotic to the line y=-4. It equals 1 when x = 0 and the rapidly climbs to + infinity. So the range is all real values greater than -4.
2007-01-19 12:58:26
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answer #2
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answered by ironduke8159 7
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0⤊
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-4
y = 5(2)^x -4
the above function is exponential function i.e. y = a* (b)^x + k its range is any set of positive real number there is no effect of shifting the function in either direction
2007-01-19 12:58:40 · answer #3 · answered by Laeeq 2 · 0⤊ 0⤋
As you wrote the function it exists for every real number so the range is the set of all real numbers
2007-01-19 12:50:34 · answer #4 · answered by santmann2002 7 · 0⤊ 1⤋
graph the equation on a calculator and it will tell you the range
2007-01-19 12:46:42 · answer #5 · answered by packattack 2 · 0⤊ 0⤋