Please I need help?

Question

Give answers in the nearest thousands

The length of one leg of a right triangle is 3in more than the other. If the length of the hypotenuse is 8in., What are the lengths of two legs?

Answer 1

use the pythagorean theorem

x^2 + y^2 =c^2

where x and y are sides and c is the hypotenuse

then you have

x=y+3

now sub all that in and you get

(y+3)^2+y^2=8^2

y^2+6y+9+y^2=64

2y^2+6y-55=0

you can now factor this out and get a value for y

Answer 2

Use the Pythagorean theorem.

a^2 + b^2= c^2 where c is the hypotenuse.

(x)^2 + (x+3)^2= 8^2
x^2+ x^2+9=64
2x^2+9=64
2x^2=55
x^2=55/2
x= square root of 55/2

For the other leg, just add 3.

Answer 3

You need to use the Pythagorean theorem and do the work yourself. Unless you have a specific question about how to use this theorem:

a squared plus b squared equals c squared

(the sum of the squares of the two sides of a right triangle is equal to the square of the hypotenuse)