find the derivative?
2007-01-19 04:32:22 · 5 answers · asked by roadcrasher 1 in Science & Mathematics ➔ Mathematics
F'(x)=e^x
The derivative of e^x is e^x and one is a constant so the derivative of 1 is 0. e^x+0=e^x
2007-01-19 04:37:22 · answer #1 · answered by Ben B 4 · 0⤊ 0⤋
the function is y= e^x+1.Its derivative is y´=e^x
2007-01-19 04:38:50 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
Depending on how you define F(x), you can have infinity number of solutions.
For example,
F(x) = 1
F'(e^x + 1) = 0
2007-01-19 05:14:59 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
F'(e^x + 1)
= F'(e^x ) +F'(1) = e^x +0 = e^x naswer.
2007-01-19 04:50:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Because F'(f0(x)+f1(x))=F'(f0(x))+F'(f1(x)), and F'(c)= 0:
F'(e^x)+F'(1)
e^x
2007-01-19 04:40:13 · answer #5 · answered by Mr. Chemistry 2 · 0⤊ 0⤋