how to solve?

Question

For the function, y=
__1__
x-2
a) Give the y values for x = -2, -1, 0, 1, 2, 3.

Answer 1

y=x-2? just instead of x put the numbers => y=-2-2 => y=-4 etc.

Answer 2

Replace x with the given values to compute y (I am assuming the formula is 1/(x-2):

when:
x = -2; y = 1/(-2-2) = -1/4
x = -1, y = 1/(-1-2)) = -1/3
x = 0, y = 1/(0-2) = -1/2
x = 1, y = 1/(1-2) = -1
x = 2, y = 1/(2-2) = 1/0 = imaginary (undefined)
x = 3, y = 1/(3-2) = 1

Answer 3

I assume you mean: 1/(x-2) correct?

First: replace each value/number with the x-variable in the expression...

a. x = - 2

1/(-2-2)

1/-4
= -1/4

b. x = - 1

1/(-1-2)

1/-3
= -1/3

c. x = 0

1/(0-2)

1/-2
= -1/2

d. x = 1

1/(1-2)

1/-1
= -1

e. x = 2

1/(2-2)

1/0
= undefined

f. x = 3

1/(3-2)

1/1
= 1

Answer 4

you must put these numbers instead x
x=-2 y= -1/4
x=-1 y=-1/3
x=0 y=-1/2
x=1 y= -1
x=2 y doesn´t exist because the denominator becomes 0 and you can´t divide by zero
x=3 y=1

Answer 5

for x=-2, y= 1/(-2-2) y=-1/4
for x=-1, y=1/(-1-2) y=-1/3
for x=0, y=1/(0-2) y=-1/2
for x=1, y=1/(1-2) y=-1
for x=2, y=1/(2-2) y doesnt exist you cant divide by zero
for x=3, y=1/(3-2) y=1

hope that helps

Answer 6

To get 1/(x-2), simply subtract 2 from x, and take its reciprocal (where the reciprocal of y is 1/y, or the solution z to zy=1, such as 1/2 is the reciprocal of 2), where defined. You don't need our help.

Answer 7

x=mp

Answer 8

what is _1_ supposed to mean?