A Basketball player shoots a basketball with a speed of 50 feet per second at an angle of 50 degrees to the ground. What is the vector that describes the motion of the basketball?
I think its something like...
50 i + 50 j
or
32 i + 32 j
I dont know and dont understand what this question is asking. Just need some help setting this one up. Thanks.
2007-01-19 02:36:43 · 3 answers · asked by Matthew B 2 in Science & Mathematics ➔ Mathematics
The vector is
(50*cos(ang),50*sin(ang))
This is the horizontal and vertical components.
The unit vector aligned horizonatal is frequently called i, and the vertical unit vector j.
Calculate those funcitons and you get:
50*cos(ang)*i + 50*sin(ang)*j
where ang = 0 is parallel with the floor, 90 deg is perpendicular to the floor, ie, straight up.
2007-01-19 15:22:34 · answer #1 · answered by modulo_function 7 · 0⤊ 0⤋
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2016-10-31 12:51:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
neither is correct.
the magnitude (x) is 50, the angle (Θ) is 50º
It's v = (x cos Θ)i + (x sin Θ)j
I might have the cos & sin reversed.
2007-01-19 02:50:31 · answer #3 · answered by bequalming 5 · 0⤊ 0⤋