A vector has the following initial and terminal points Respectively : Initial point: (-1,1) Terminal point (2,-2)
Im looking for the position vector?
I dont know how to figure this one out? Just need help setting up the problem and answering it. Thanks.
2007-01-19 02:32:06 · 4 answers · asked by Matthew B 2 in Science & Mathematics ➔ Mathematics
(2-(-1), -2-1)
the position vector is (3,-3)
2007-01-19 02:38:08 · answer #1 · answered by iyiogrenci 6 · 0⤊ 0⤋
The slope of this vector is (1-(-2))/ (-1-2)= -1and its length
d= sqrt (-1-2)^2 +(1-(-2))^2 =sqrt 18
2007-01-19 05:44:19 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
position vector is (x2- x1)i + (y2 - y1)j Substituting [4-(-a million)] i + [6 - 2] j 5i + 4j sure, you've been ideal as a change of declaring position vector, it will be known because the displacement vector.
2016-10-17 02:16:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Why oh why did I cheat my way through math class :(
2007-01-19 02:37:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋