2007-01-19 00:04:43 · 6 answers · asked by Denielle B 1 in Science & Mathematics ➔ Physics
The change in x is -4 - 3 = -7
The change in y = 5 - -4 = 9
Using pythagoras, the distance is √(7² + 9²)
= √(49 + 81)
= √130
or about 11.4
2007-01-19 00:09:35 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
Use the formula PQ= (X2-X1)2 +(Y2-Y1)2
P=(X1,Y1)
Q=(X2,Y2)
(X2-X1)2 +(Y2-Y1)2 - this part is within the square root.
and the 2 outside the parentheses is square.
and the 2 below the constants is below the constant.
I am sorry this is hard to explain
This is the best I could do!!
2007-01-19 00:15:13 · answer #2 · answered by bluekiwi 2 · 0⤊ 0⤋
d=sqrt( (3 +4)^2 +(5+4)^2)= sqrt 130
2007-01-19 00:11:11 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
oh good! I just did this in my pure math class under co-ordinate geometry and im 16
the equation for this is hard to type
the answer is \/130(the answer should always be positive cos its a Length)
I hope this is what you need. ( " \/ " MEANS SQUARE ROOT)
2007-01-19 00:41:37 · answer #4 · answered by bitter > sweet > cold 2 · 0⤊ 0⤋
â((x2-x1)^2 + (y2-y1)^2)
â((-4-3)^2 + (5 - - 4)^2)
â((-7)^2 + (9)^2)
â(49) + (81)
â130
11.4
2007-01-19 07:28:20 · answer #5 · answered by Anonymous · 0⤊ 0⤋
use distance formula,that's it
2007-01-19 00:31:05 · answer #6 · answered by neeraj_agarwal_1990 1 · 0⤊ 0⤋