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A bacteria culture starts with 1000 bacteria. Two hours later there are 1500 basteria. Finf an exponential model for the size of the culture as function of time t in hours, and use the model to predict how many bacteria there will be after two days.

2007-01-18 19:36:02 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

Exponential functions mean the equation will look like f(t)=1000*k^t in order to create an exuation you need to find k

Put in the 1500 and the 2 hours: 1500=1000k^2
Solve for k: k^2=1.5 k=1.2247
f(t)=1000*1.2247^t

Put in 48 hours for 2 days: 1000*1.2247^48=16834112 bacteria after 2 days.

2007-01-18 19:59:00 · answer #1 · answered by Ben B 4 · 0 0

let time interval "unit" = 2 hours
k = 1.5 [this is the 'proportion of increase" for a "unit-time"]

S = starting number

f(t) = S * k^t

two days = 48 hours => t = 24

f(24) = s * k^24 = 1000 * (1.5)^24
f(24) = 1000 * 16834.112 = 16834112

so after 2 days there will be 16,834,112 bacteria

2007-01-19 03:43:04 · answer #2 · answered by atheistforthebirthofjesus 6 · 0 1

y = 1000 * sqrt(1.5)^t

This will explain the number after 2 hours. sqrt is of course the squared root and ^ the power. The total number after two days will be:

y = 1000*sqrt(1.5)^48 = 16.834.112

2007-01-19 03:49:56 · answer #3 · answered by bobmiep 1 · 0 0

Let

t = time
N = number of bacteria at time t

N = 1000e^(kt)
1500 = 1000e^(2k)
e^(2k) = 1500/1000 = 3/2
ln{e^(2k)} = ln(3/2)
2k = ln(3/2)
k = (1/2)ln(3/2)

N = 1000e^(kt)
N = 1000e^{(1/2)(ln(3/2))t} = 1000e^{(t/2)(ln(3/2))}

After two days t = 48 hours

N = 1000e^{(48/2)(ln(3/2))} = 1000e^{(24)(ln(3/2))}
N = 16,834,112

2007-01-19 03:56:02 · answer #4 · answered by Northstar 7 · 0 0

N = ab^t
1500 = 1000b^2
b^2 = 1.5
b = 1.22474
N = 1,000(1.5)^t/2, t in hours
N = 1,000(1.5)^24
N = 16,834,112

2007-01-19 04:12:48 · answer #5 · answered by Helmut 7 · 0 0

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