Help In Algebra?

Question

I'm in middle school in 7th grade.

Directions: Write an equation in standard form, containing the given point an having the given slope.

1. (3,1) m=2
Answer provided by the teacher: 2x-y=5, y=2x-5


The thing is that I don't know HOW to do it. Could someone EXPLAIN to me how to solve this? Thanks. Most through answer gets 10 points

Answer 1

Use the PONT-SLOPE form of the linear equation. Because, the givens are a point and a slope.

The point slope form is y- y1 = m(x - x1)

Now the given point (3,1) corresponds to (x1,y1)

Substitute and you get y -1 = 2 (x -3). Distribute the 2, you get
y -1 = 2x -6
Add 1 to each side and you get y = 2x - 5.

Extra info. If you are given two points, use the 2 point form of the linear equation where you need the calculate the slope first from the 2 points; if you are given the x and y intercepts, use the intercept form, etc.

Answer 2

standard form is y = mx + b, where m is the slope and b is the y-intercept.

you are given slope, therefore:
y = 2x + b

next, you need to find b. Since this is an equation of a line and the point (3,1) is on the line, those values can be substituted in to find b:
1 = 2(3) + b
1 = 6 + b
b = -5

Therefore, the standard equation is:
y = 2x - 5

Answer 3

First, put the point into slope intercept form, which is y=mx+b. It coordinates you gave are the (x,y). Now, plug those values and the m value into the equation to solve for b. Then, you write the y=mx+b,again, except this time, with the m and b values in there.

For standard form, you have to bring the x and y variables to 1 side, while having the constant on the other.

Answer 4

you need to use point slope form in such a problem.
formula is:(y-y1)=m(x-x1), y1=y coordinate and x1=x coordinate
(y-1)=2(x-3)
y-1=2x-6
-1+6=2x-y
5=2x-y
so,equation is 2x-y=5 or
2x-5=y.

Answer 5

For increasing cubic binomials the familiar formula is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D

Answer 6

common equation:
y=mx+c

point (3,1)

3=x
1=y

m=2

Put it into the common formula;;

1=2(3)+c

c=-5

c is a number.. It's not a variable..

y=2x-5