2007-01-18 17:03:00 · 3 answers · asked by Rao M 1 in Science & Mathematics ➔ Physics
In a diode the voltage is controlled by the diode. The voltage you mentioned must be for a specific current. So hook the diode into a circuit which provides the correct current and the voltage across the diode will also be as specified.
2007-01-18 17:08:22 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋
Just going off the top of my head, but 1100 mV seems kinda high for a forward biased pin diode, but maybe I'm just too old to remember stuff like that. I thought it was about 700mV.
I'm sure you already know this, but diodes are made from the combination of P and N type materials. The extra electrons in the N and the extra holes in the P are created through the processes of doping and lacing. Basically, you add some impurity to the silicon semiconductor to create the different regions. The more impurities you place in the device, the more collisions will occur when you try to drive it. This results in an increased resistance to current flow and will raise the voltage drop. So if you had a heavily doped diode you could possibly get there.
Are you asking this as a final question or are you trying to make a voltage drop in a circuit, or something else?
2007-01-19 13:03:14 · answer #2 · answered by TKA 2 · 0⤊ 0⤋
plug that diode into a wall outlet, but first ground yourself to a appliance, like the bathtub, don't do this if you have any company over, always think about safety first.
2007-01-26 22:55:11 · answer #3 · answered by fresh 2 · 0⤊ 0⤋