The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5cm, what are the dimensions (the length and width) of the rectangle?
2007-01-18 16:36:47 · 7 answers · asked by badmf777 1 in Science & Mathematics ➔ Mathematics
I'm not doing your homework for you...
2007-01-18 16:39:28 · answer #1 · answered by USAF, Retired 6 · 3⤊ 0⤋
3 and 4
2007-01-19 00:39:53 · answer #2 · answered by Critical Mass 4 · 1⤊ 0⤋
let say width is w
then length is w +1.
diagonal is w^2 +(w+1)^2=5^2
Then You'll get 2w^2 +2w+1=25
make it 2w^2 +2w-24=0
factorise it. (w-3)(w+4)=0
now w=3 or w= -4
as w is length it cannot be negative so w = 3
length is w+1= 4
2007-01-19 00:45:45 · answer #3 · answered by mathavan velayutham 2 · 0⤊ 0⤋
w = width
w+1 = length
diagonal = sqrt(w^2 + w^2 + 2w +1)
5 = sqrt( 2w^2 +2w+1)
25 = 2w^2 +2w+1
2w^2+2w -24 =0
w^2+w-12=0
(w+4)(w-3) = 0
w=3 = width
w=1 = 4 = length
2007-01-19 00:43:55 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Basically, pythagorean theorem
Let x = length of width
x squared plus (x+1) squared equals five squared.
if you pythagorean triples, you would know that 3,4, and 5 work
(3+1 = 4)
answer is 3 by 4
2007-01-19 00:40:45 · answer #5 · answered by smartyoshi7 1 · 0⤊ 0⤋
let the width be x
The length is x+1
Diagonal is 5 cm
by pythagoras theorem
x(sqrd)+(x+1)(sqrd)=25
X=3
2007-01-19 00:43:51 · answer #6 · answered by Kaiser Abhishek 1 · 0⤊ 0⤋
length=4cm, width=3cm. This is a classic Pythagorean 3,4,5 right triangle.
2007-01-19 00:41:00 · answer #7 · answered by spyguy 3 · 0⤊ 0⤋