Finding the mass of steam needed to mix with ice to produce 35 deg. C water?

Question

What mass of steam at 100.°C must be mixed with 175 g of ice at its melting point, in a thermally insulated container to produce liquid water at 35°C? (g)

Answer 1

You need 35% steam and 65% ice to make water at 35 degrees

So if there are 175g of ice
then you need 175g / 65% = 2.7g/% x 35% = 94.23g of steam

Answer 2

Its late for me to do the calculation for you, but this is the method.

1. calculate the heat to melt the ice (175 g x heat of fusion of ice)

2. calculate the heat to raise the melted ice water from 0 Celsius to 35 Celsius.

3. Add these 2 together and you have the total heat absorption. This heat has to come from the condensation of the steam and the resulting hot water being cooled to 35 C.

4. You can also go backwards and calculate the quantity of water that would be heated from 35 C to 100 C and then converted to steam (heat of vaporization).

The whole thing becomes an equation with one unknown.