The car moved 2km towards east made a perpendicular left turn ran for 500mmade a perpendicular right turn ran for 4 km and stopped. find the displacement of car
2007-01-18 14:35:09 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
just add the numbers 2k+500m+4k= 6.5KM,
actually I was Kidding the right answer is 6.02079 Km
and the angle is 57.29 North East
2007-01-18 14:44:08 · answer #1 · answered by Anonymous · 0⤊ 1⤋
The total distance that the car travelled towards east is 6 km, and that towards north is 500 m or make it 0.5 km
we can find the displacement here by using the pythagoras theorom...
(Total Displacement)^2 = 6^2 + 0.5^2 = 36.25
Total Dispalcement = 6.02079728939 km
2007-01-22 15:28:11 · answer #2 · answered by plato's ghost 5 · 0⤊ 0⤋
total it travels 6 km eastward and 500m or 0.5 km northwards. total displacement is sqrt (36+0.25)=6.25km. Direction is east tilting towards north by an angle of (90- tan-1 (12)).
2007-01-19 03:07:37 · answer #3 · answered by Lovleena G 2 · 0⤊ 0⤋
----------------------------------
I 4km
0.5km I First car moves 2km
----------------I east as shown in the figure 2KM then .5 km left and then the distance between the intial point and the final point is known as displacement hence a line drawn between these points will intersect at 1/3 of 0.5km i.e .17 km as the ndistances are 2 and 4 . the line will intersect in the ratio 1:3. hence the solution is as follows
applying pythagorus therom 2*2+0.7*0.7 =4.49 applying pythagorus therom 4*4+0.34*0.34=16.1036 hence the solution is 4.49+16.1036=20.5036
2007-01-18 23:53:55 · answer #4 · answered by Syed Shoeb P 1 · 0⤊ 0⤋
the final displacement is 600 m east and 500 m south
or if you want a one-directional displacement 538.52 m south east
2007-01-18 22:41:07 · answer #5 · answered by shelly 4 · 0⤊ 0⤋
add up the east values, then add the south value. Then use vector addition on the two using the distance formula (pythagorean theorem)
2007-01-18 22:38:38 · answer #6 · answered by polevaulter1000 3 · 0⤊ 0⤋
We can apply pythagoras theprm and the answer comes out to be 4.25km
2007-01-19 00:56:29 · answer #7 · answered by ? 2 · 0⤊ 0⤋