does anyone know this???? It's a quiz survey?

Question

the calculaters for patty's store are packaged in 15 to a box, and batteries are 144 to a box. Each calculater requires 4 batteries. What is the least number of boxes of calculaters she will need if she wants no calculaters or batteries left over?
Possibilities(choices)
A. 4 boxes
B. 6 boxes
C.12 boxes
D. 180 boxes

Answer 1

144 batteries per box divided by 4 means each box will power 36 calculators.

Now you want to figure the lowest common multiple of 36 and 15. You could do it the long way as follows:

Multiples of 15:
15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, ...
Multiples of 36:
36, 72, 108, 144, 180, ...

Ah, there's the answer that when we have 12 boxes of 15 calculators (180) it will equal the 5 boxes of 36 battery sets (180).

The shortcut is to take the prime factors of the two numbers:
15 = 3 x 5
36 = 2 x 2 x 3 x 3

Now to "cover" both numbers you need two 2s, two 3s and a 5. That's 2 x 2 x 3 x 3 x 5. If you multiply it out it is 180 calculators and therefore 180 battery "sets".

180 / 15 = 12 boxes of calculators
180 * 4 / 144 = 5 boxes of batteries

So the answer is:

c. 12 boxes of calculators

Answer 2

12 boxes