write the slope-inersept form of an equation of the line that passes through the given point and is parallel to the graph of each equation
(3,3),y =2/3x - 1
2007-01-18 12:39:37 · 4 answers · asked by cristina 3 in Science & Mathematics ➔ Mathematics
Point-slope form:
y-y1=m(x-x1)
y-3=2/3(x-3)
y-3=2/3x-2
y=2/3x+1
2007-01-18 12:45:51 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Since it is parallel to the following line y=2/3-1, then the slope must be 2/3.
And if it passes through the line 3,3 and if you follow the slope patern, 2/3 the y-intercept will be 1.
So y=2/3+1
2007-01-18 21:32:19 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Since the line is parallel to y=2/3x -1 the line also has slope =2/3.
thus y= 2/3x +b Now plug in x=3 and y=3 getting
3= (2/3)(3) +b --> b= 3-2 = 1
So equation is y = 2/3x +1
Just another way to get the answer.
2007-01-18 20:57:49 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
it is
(L) : y = mx + t
(L) || y = 2/3x -1
=> m = 2/3
(L) passes through (3,3)
=> 3 = 2/3 * 3 + t => t = 1
the line found : (L) y = 2/3x + 1
2007-01-18 21:22:50 · answer #4 · answered by James Chan 4 · 1⤊ 0⤋