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Theres a regular 3 and the the cube root symbol all over 5y^3 times a regular 2 then the cube root symbol all over 50y^4

2007-01-18 12:32:32 · 1 answers · asked by Eric K 2 in Science & Mathematics Mathematics

1 answers

So you mean:

3 ³√(5y³) × 2 ³√(50y⁴)

Right?

If so, you can do the stuff outside and inside:

3(2) ³√[(5y³)(50y⁴)]

6 ³√(250y^7)

Then 250 = 125 × 2 = 5³ × 2:

6 ³√((5³ × 2)y^7) = 6 ³√5³(³√2)(³√y^7) =

30³√2y^(7/3)

2007-01-18 16:33:08 · answer #1 · answered by Jim Burnell 6 · 0 0

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