Finding slope of line that is perpendicular?

Question

x+6y=6 & 4y-6x=12 PLZ show work

Answer 1

The slope of a perpendicular line is the opposite reciprical of the slope of the line it is perpendicular to.

x + 6y = 6...must put in y=mx+b form
6y = -x + 6
y = (-1/6)x + 1 .......the -1/6 is the slope of this line
Slope of line Perpendicular would be 6.

4y - 6x = 12
4y = 6x +12
y = (3/2)x + 3......the 3/2 is the slope of this line
Slope of line Perpendicular would be -2/3

Answer 2

First, the slope of a line = rise over run. If the line is perpendicular it will never run, so you would have like 5/0. Therefore the slope of a perpendicular line is undefined.

x+6y=6
4y-4x=12

To get slope easily, get into y=mx+b form, and m will be the slope
x+6y = 6
6y = -x+6
y = -1/6x + 6, so this slope is -1/6 or down 1 and right 6

4y-6x=12
4y=6x+12
y = 6/4x + 12/4
y = 3/2x + 3, so this slope is 3/2 or up 3 and right 2. These lines will cross since there slopes are different.

Note a line that is perpendicular is usually in x=n form where n is any number. Then this line will be perpendicular to the x axis.

Answer 3

first get y by itself.
Slope is the coeffecient of x (the number in front of x)
To find the slope of the line perpendicular, you flip the fraction over and change it's sign. Sooo if you had slope of -1/6, the perpendicular would be 6/1, or just 6.