The magnitude of each of the charges in the figure is 9.00x 10^-12 C. The lengths of the sides of the rectangle are 3.00 cm and 6.00 cm. Find the magnitude of the electric field at the center of the rectangle in figures a and b.
figure a= 143.84 N/C
figure b = ___________N/C
http://www.webassign.net/CJ/18-21fig.gif
I have solved part A and I'm sure that it factors into part B somehow, but I have no idea how to proceed with solving part B. I am in desperate need of some guidance here!
My line of thinking is that I need to find the angle of the electric field, which I believe to be 26.6 degrees. Not sure if that is correct. There is no x-component to the electric field, but there is a y component which I think is obtained by 143.84sin(26.6)= 64.405. Problem is that I'm still getting a wrong answer, so I must be doing something wrong. Can anyone point me in the right direction?
2007-01-18 11:22:59 · 2 answers · asked by larkinfan11 3 in Science & Mathematics ➔ Physics
You're doing fine up to sin26.6. It should be sin63.4
Your equation will give you the vertical component of one of the charges. Multiply by 2 to get the total field strength in an upward direction.
2007-01-18 13:34:38 · answer #1 · answered by Steve 7 · 0⤊ 0⤋
sorry dont know
2007-01-18 19:32:11 · answer #2 · answered by D M 2 · 0⤊ 0⤋