An infinite number of them.
Divide the triangle in 2.
Then divide each of those triangles in 2.
Then divide each of those triangles in 2.
And so on...
2007-01-18 09:44:41
·
answer #1
·
answered by Mark P 5
·
2⤊
0⤋
An infinite number.
Take the mid point of each side and connect these points. You have now divided the original triangle into congruent triangles and each of these is similar to the original big triangle.
You can now repeat this for each the four triangles and you get 16 triangles each congruent and similar to the original triangle.
This is an example of what is known as a fractal where the pattern repeats itself every time you look closer.
2007-01-18 19:58:05
·
answer #2
·
answered by RATTY 7
·
0⤊
0⤋
Only one triangle can fit into a triangle the sides of which are equal to the one triangle.
2007-01-18 09:50:01
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
If the equal sided triangle had the measurements of Infinity+Infinity+Infinity then every triangle that ever existed would fit inside!
Except the one that is infinite of course.
2007-01-18 09:46:08
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
Infinitely many, depending on the size of the interior triangles and assuming they're equilateral
2007-01-18 09:44:50
·
answer #5
·
answered by MateoFalcone 4
·
1⤊
1⤋
Depends how big the triangles are.
2007-01-19 04:51:28
·
answer #6
·
answered by bird brain 2
·
0⤊
0⤋
Impossible to answer.
You could say 1 if it is the same size, or 50,0000 if they are all the size of a pin head for example
2007-01-18 09:45:22
·
answer #7
·
answered by spiegy2000 6
·
0⤊
0⤋
in theory infinnanet number of trianges, but i know to devide it simply tou can have 4 triangels inside, then one that contains them all, so 5 is the total.
2007-01-18 09:46:58
·
answer #8
·
answered by Anonymous
·
0⤊
2⤋
Here's a better one
How many toblerones can venessa feltz stick into her orrafice
2007-01-18 09:47:11
·
answer #9
·
answered by Anonymous
·
0⤊
2⤋
as many as you want ! you need to put dimensions in the question
2007-01-18 10:38:13
·
answer #10
·
answered by william k 1
·
0⤊
0⤋