A boy ate 100 cookies in five days. Each day he ate 6 more than the day before. How many did he eat on Day 1?

Question

Pleese help. need Help.

Answer 1

He ate 8 cookies on day one.

8+14+20+26+32=100

Answer 2

OK, let's set this one up correctly.

On day 1 he ate X cookies, so on day 2 he ate X + 6, etc.
So he ate X + (X+6) + (x+12) + (X+18)+ (X+24) = 100 total, or
5X + 60 = 100, or X = 8. So on day 1 he ate eight cookies, day two=14, day 3=20, day 4 =26, day 5=32.

To check 8 + 14 + 20 + 26 + 32 = 100? yes. correct.

Answer 3

Eight.

8+6 = 14+6 = 20+6 = 26+6 = 32

8+14+20+26+32 = 100

(Unless there's some real trick like him needing to eat 6 more on Day One on top of what he'd already eaten!)

Answer 4

a = day 1 ; b = day 2 ; c = day 3 ; d = day 4 ; e = day 5

a + 6 = b ; b + 6 = c ; c + 6 = d ; d + 6 = e

a + b + c + d + e = 100
a + (a+6) + (b+6) + (c+6) + (d+6) = 100
a(2) + 6 + [(a+6)+6] + [(b+6)+6] + [(c+6)+6] = 100
a(3) + 18 + [(a+6)+12)] + [(b+6)+12] = 100
a(4) + 36 + [(a+6)+18] = 100
a(5) + 60 = 100
a(5) = 60
a = 8

day 1: 8
day 2: 8 + 6 = 14
day 3: 14 + 6 = 20
day 4: 20 + 6 = 26
day 5: 26 + 6 = 32

8 + 14 + 20 + 26 + 32 = 100

Answer 5

Set it up as x+(x+6)+(x+6+6)+(x+6+6+6)+(x+6+6+6+6)=100

That becomes -->5x+60=100

Subtract 60 from both sides --> 5x+60-60=100-60

That becomes --> 5x=40

Divide both sides by 5 --> 5x/5=40/5

That becomes x=8

So the boy ate 8 cookies on Day 1.

Answer 6

D1 + (D2+6) + (D3+12) + (D4+18) + (D5+24) = 100
5D + 60 = 100
5D = 40
D=8
Proof - 8 + 14+ 20 + 26 + 32 =100

Answer 7

100=x+ (x+6)+ (x+12)+ (x+18)+ (x+24)
100=5x + 60
40= 5x
8 = x

He ate 8 cookies the first day

Answer 8

it doesn't count number that he began with 8 cookies, the position are his mom and father, and do they understand the way many cookies he has eaten in below a week? except they are the girlscout cookies that I nonetheless have a collection of...tupid, tupid girlscouts!

Answer 9

One