a. x^2 + 2xy - 7
b. 2x^2 + 2xy + 7
c. x^2 + 6xy -7
d. x^2 + 6xy + 1
2007-01-18 09:19:12 · 12 answers · asked by last3member2002 1 in Science & Mathematics ➔ Mathematics
Dealing with 'like' terms, subtract the second expression from the first.
2x^2 + 4xy - 3
x^2 - 2xy - 4
- - - - - - - - - -
x^2 + 6xy + 1
2x^2 - x^2 = x^2
4xy - (-2xy) = 6xy
- 3 - (-4) = 1
2007-01-18 09:29:14 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The answer is D. I would line up the two problems vertically
2x^2 + 4xy - 3
x^2 - 2xy - 4
Then, I find most people have an easier time adding, so you could change all the signs on the bottom trinomial, to make it a little easier.
2x^2 + 4xy - 3
-x^2 + 2xy + 4
x^2 + 6xy + 1
2007-01-18 09:54:55 · answer #2 · answered by leo 6 · 0⤊ 0⤋
(d), to attain at this, subtract both equations, you subtract by technique of reversing the indicators and including. 2x^2 + 4xy -3 -(x^2 - 2xy -4), it truly is 2x^2 + 4xy -3 -x^2 + 2xy +4 or x^2 + 6xy + a million it truly is answer D.
2016-10-15 10:17:43 · answer #3 · answered by Anonymous · 0⤊ 0⤋
2x^2 + 4xy - 3-( x^2 - 2xy - 4)Put in () because subtracting the whole
2x^2 + 4xy - 3 -x^2+2xy+4 Distribute the negative
x^2+6xy+1 Combine like terms
d
2007-01-18 09:25:05 · answer #4 · answered by CC 2 · 0⤊ 0⤋
2x^2 + 4xy - 3 -( x^2 - 2xy - 4 )
x^2+6xy+1
d. x^2 + 6xy + 1 is correct
2007-01-18 09:25:04 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
d.
(2x^2 + 4xy - 3) - (x^2 - 2xy - 4)
= (2-1)x^2 + (4-(-2))xy + (-3-(-4))
= x^2 + 6xy + 1
2007-01-18 09:23:06 · answer #6 · answered by Anonymous · 1⤊ 0⤋
That the coefficients are different!
2007-01-18 09:23:49 · answer #7 · answered by gianlino 7 · 0⤊ 0⤋
Ummmm... yeah whatever they said.
2007-01-18 09:26:53 · answer #8 · answered by Skippy 2 · 0⤊ 1⤋
d
2007-01-18 09:24:41 · answer #9 · answered by sillycanuckpei 4 · 0⤊ 1⤋
d
2007-01-18 09:24:02 · answer #10 · answered by Dupinder jeet kaur k 2 · 0⤊ 1⤋