The vertex form of a quadratic function is 3(x-7)^2-4. Find the usual y=ax^2+bx+c form of the quadratic.?

Answer 1

It seems that all you need to do here is a little bit of algebra manipulation.
You are starting with this expression:
3 (x - 7)^2 - 4

First, expand the (x - 7)^2 part of it:
3 (x^2 - 14x + 49) - 4

Next, distribute the factor of 3:
3x^2 - 42x + 147 - 4

Finally, simplify the 147 - 4 part of it:
3x^2 - 42x + 143

Answer 2

Foil out the (x-7)^2
Then multiply the result by 3
Then subtract 4.