For 7 you have 6 possibilities out of 36 but for 10 you have only 3. So 9/36 =1/4
2007-01-18 04:10:19
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answer #1
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answered by gianlino 7
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There are 6 numbers on each die, so there are 36 different combinations, if for example you consider "2 on the first die, 5 on the second die" to be different than "5 on the first die, 2 on the second die".
There are several different ways you can roll a seven: 1 and 6, 2 and 5, or 3 and 4. Since it doesn't matter which die gives us which number, there are 6 total possibilities. Likewise, there are different ways you can roll a ten: either a 4 and a 6, or 5 and 5. But in this case there are 3 total possibilities (4 on the first die and 6 on the second, 6 on the first die and 4 on the second, or both dice coming up as a 5).
So there are 9 different ways total of getting either a 7 or a 10. Since there are 36 different combinations possible, the probability is 9/36, or 1/4.
2007-01-18 04:26:59
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answer #2
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answered by Anonymous
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There are 36 possible combinations. The ones that make 7 are 1/6, 2/5, 3/4, 4/3, 5/2 and 6/1. A total of 6, so a 1in 6 chance. For a 10, 4/6, 5/5 and 6/4 a total of 3 so a 1 in 12 chance.
for the two combined, it is 1 in 4 chance.
2007-01-18 04:11:25
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answer #3
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answered by Elizabeth Howard 6
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2 dice
6 sides each
36 possible combos
6 combos = 7
3 combos = 10
6+3=9
9 out of 36 = 7 or 10
9 ~ 36 is same as 1 ~ 4
so its 1 outa 4 chance that the roll will be 7 or 10
2007-01-18 04:11:12
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answer #4
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answered by rollerskater 3
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1/6+1/6
1/3
2007-01-18 04:05:46
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answer #5
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answered by wind_liao 2
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