2007-01-18 03:58:18 · 3 answers · asked by ufc_babe 2 in Science & Mathematics ➔ Physics
the latent heat of fusion for water-ice is 80 cal/g. This means that 80 of the calories are used just to turn the ice at 0 C into water at 0 C. Since a calorie raises 1g of water 1degree C, the water will be 20 C.
2007-01-18 04:07:57 · answer #1 · answered by Gerfried 2 · 0⤊ 0⤋
If the water is in the liquid section, it has a undeniable heat temperature of one million calorie in conserving with gram degree C. the dating between heat temperature, particular heat temperature, mass and regulate in temperature is H = m c (replace in T) So replace in T = H/mc the proper answer is b. as properly the reality that it would decide to be written as 2 C ranges not 2 ranges C for this reason of the reality that's a replace in T, not a T analyzing.
2016-12-16 07:35:00 · answer #2 · answered by zell 4 · 0⤊ 0⤋
Latent heat of fusion is about 80 cal/g so the final temperature will be 20 deg C.
2007-01-18 04:08:52 · answer #3 · answered by gebobs 6 · 0⤊ 0⤋