distance problem?

Question

A skier is gliding along at 3.0 m/s on horizontal, frictionless snow. He suddenly starts down a 10 degree incline. His speed at the bottom is 15 m/s. how long in the incline and how long does it take him to get to the bottom?

Answer 1

Accereration down the incline
= g sin10
= 1.7034 m/s^2


(vf)^2 = (vi)^2 + 2ax
vf = 15 m/s
vi = 3 m/s
a = 1.7034 m/s^2

Solve for x
x = 63.4 m

Answer 2

His acceleration is 9.8sin30 =1.7m/sec^2

Vf = Vo + at

t = (Vf - Vo)/a = 12/1.7 = 7 sec

x = Vo*t + 1/2*at^2 = 63m