If a triangle is 10 feet by 5 feet , what is the measurement between opposite corners and how do you find it?
2007-01-18 02:31:38 · 7 answers · asked by Jeffer 2 in Science & Mathematics ➔ Mathematics
Need more info - is it a right triangle and are 10 ft and 5 ft the length of the sides?
2007-01-18 02:39:40 · answer #1 · answered by mortgagelns 3 · 0⤊ 0⤋
Are you sure it's a triangle you're asking about? Triangles aren't usually measured in lengths like "10 ft by 5 ft", because it's not clear what this is measuring. Is it one of the sides and the height relative to this side? For that matter, there are no "opposite corners" on a triangle, since each corner is adjacent to the other two.
2007-01-18 10:39:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I assume the triangle has a base of 10 feet and an altitude of
5 teet and the triangle is isosceles. Otherwise, it is not a solvable problem
So the two equal sides of the triangle are each sqrt(50)
= 5*sqrt(2) feet in length.
2007-01-18 10:40:24 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
if it´s a right angled triangle, and the 10 and 5 are the right angled sides, then the diagonal is the sqaure root of the the sum of the 2 sides squared. ie sqrt (100+25)
2007-01-18 10:42:34 · answer #4 · answered by gavan m 1 · 0⤊ 0⤋
what do you mean by 10 feet by 5 feet?
2007-01-18 10:36:09 · answer #5 · answered by mani 1 · 1⤊ 0⤋
if it is a right triangle you use 180 minus 90.
2007-01-18 10:54:44 · answer #6 · answered by Jeremy's gurl 2 · 0⤊ 0⤋
From solution of triangles we have
a,b,c are sides
A,B,C are opposit angles
respectively
[a/sinA]=[b/sinb]=[c/sinC]
Here using data given we can
write
10/sinA=5/sinB
data is not enough to solve
2007-01-18 10:39:14 · answer #7 · answered by openpsychy 6 · 0⤊ 0⤋