x= -b + {b"2 -4ac}
2a
2007-01-18 01:34:17 · 5 answers · asked by kindfirez 3 in Science & Mathematics ➔ Mathematics
You meant
x 1,2= (-b + (b^2 -4ac))/2a
as a solution ( roots ) to quadratic equation of general form
ax^2 + bx + c=0
2007-01-18 01:47:31 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
x=[-b + {b"2 -4ac}^ ( ½)]/ 2a
2ax = [-b + {b"2 -4ac}^ ( ½)]
b + 2ax = {b"2 -4ac}^ ( ½)
Squaring both sides,
b^2 + 4abx + 4 a^2x^2 = b"2 -4ac
4abx +4 a^2 x^2 = -4ac
bx + a x^2 = -c
a x^2+ bx +c= 0
2007-01-18 21:28:23 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
x= -b + {b"2 -4ac}/2a
this is a quadratic formula
2007-01-18 09:46:18 · answer #3 · answered by SAI S 1 · 0⤊ 0⤋
um... ax²+bx+c=0? It's difficult to answer when you do not provide the question.
2007-01-18 09:42:34 · answer #4 · answered by Pascal 7 · 0⤊ 0⤋
what is the question?
2007-01-18 09:42:31 · answer #5 · answered by iron_pennywise 1 · 0⤊ 0⤋