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5 answers

(-5,0)
x = r cos θ
y = r sin θ

2007-01-18 01:05:32 · answer #1 · answered by vincent 4 · 0 0

The change of variable "formula" is x = r cos \theta, and y = r sin \theta, thus you can change (5,pi) to x = 5 cos(pi) = -5 and y = 5 sin(pi) = 0 which yields the coordinate of (-5,0).

2007-01-18 09:06:37 · answer #2 · answered by goldenflaws 2 · 0 0

The third answer is correct.

But be careful: if you do any of this on a calculator (like a Ti-85), make sure your angles are set to radians and not degrees.

2007-01-18 09:07:05 · answer #3 · answered by wheresdean 4 · 0 0

5cos(pi)+5sin(pi)
by formula
rcosx+rsinx

2007-01-18 09:05:05 · answer #4 · answered by amit m 1 · 1 0

norm=r=5
angle=a=pi

x=rcosa=5cos180=-5
y=rsina=5sin180=0

x^2+y^2=25

2007-01-18 09:06:54 · answer #5 · answered by iyiogrenci 6 · 0 0

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