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4 answers

possible outcomes=36
favuorable outcomes=10i.e(1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (3,1) (3,2) (4,1)
p(sum of 5 or less)=10/36
=5/18

2007-01-18 01:14:02 · answer #1 · answered by karikool 3 · 0 0

in total there are 6*6=36 possible combinations
the combinations that have sum 5 or less are:
sum 2: 1-1
sum 3: 1-2; 2-1
sum 4: 1-3; 2-2; 3-1
sum 5: 1-4; 2-3; 3-2 ; 4-1

so 10 comb out of 36=> the probability is 10/36=5/18

2007-01-18 01:13:07 · answer #2 · answered by iron_pennywise 1 · 1 0

10 / 36 = 5/18

2007-01-18 01:08:32 · answer #3 · answered by gianlino 7 · 1 0

everyone did a good job. the answer is correct with certainty.

2007-01-19 14:10:01 · answer #4 · answered by e_kueh 2 · 0 0

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