twice the product of two consecutive positive odd integers is 646. find the integers?

Question

complete solution please

Answer 1

2 * 17 * 19 = 626
Therefore, the integers are 17 and 19

Answer 2

Consecutive Positive Odd Integers

Answer 3

an odd integer is has the expression (2n-1) .The next odd integer is 2n+1 so
2(2n-1)(2n+1)= 646===> 4n^2-1 =323 n^2 = 81 n=9

The numbers are 17 and 19

Answer 4

Twice any number is even number.

Subtracting and adding one to that gives us two consecutive odd numbers.

Hence the numbers are 2n-1 and 2n+1.

Twice their product is

2 (2n-1) (2n+1) = 2 (4 n^2 -1) = 646.

(4 n^2 -1) = 323

4 n^2 = 324

n^2 = 81

n = plus or minus 9.

Taking n = 9

we get 2n-1=17
and 2n+1 = 19.

Answer 5

Let x be one number so the other is x+2.
So the product is 323.
Then trial and error is probably the easiest eg square root 323 is about 18.

so try 17*19=323!

Answer 6

let the positive NO be n,so negative NO. be n+1
2[(n)(n+1)]=646
2[n^2+n]=646
2n^2+2n-643=0
2(n^2+n-323)=0
n^2+n-323=0
factor and tere's the answer
clue:-17 x 19 may be the answers

Answer 7

2(n)(n+2)=646
2n^2 + 4n - 646 = 0

solve for n using quadratic equation.

Answer 8

2(n)(n+1)=646
2n^2 + 2n - 646 = 0

on solving u get......

17 and 19........