Please show me complete working . Good luck in solving.
2007-01-17 22:37:29 · 6 answers · asked by Tuhak 1 in Science & Mathematics ➔ Mathematics
Heh, I'm actually doing this homework right now. If you could tell me how to do it on a calculator, that would be awesome.
Think of this logically rather than strictly mathematically. If you've got 1^1 (1), 2^2 (4), 3^3 (9) and so on, when you get to n^n, if you have no endpoint, then you've got infinity^infinity. Which means you can't get a sum.
If you have an endpoint, that is a completely different story.
2007-01-17 22:43:10 · answer #1 · answered by Sarah 5 · 0⤊ 1⤋
For the first person 3^3 is 27 not 9.
3 cubed is 3X3X3=27
2007-01-18 07:32:55 · answer #2 · answered by mrjomorisin 4 · 0⤊ 0⤋
this will be the series n^n.
the series diverges by n^th term test.
this series means that n increases without bound.
therefore, the sum is infinity.
2007-01-18 06:59:56 · answer #3 · answered by kimjay_lmr01 1 · 0⤊ 0⤋
n (n+1) ( 2n+1) /6.
Check the formula by inference method.
2007-01-18 08:57:42 · answer #4 · answered by Pearlsawme 7 · 0⤊ 0⤋
if i will show more nice quastion then what will u do.....
don't be kid ,such type of problems are showing that u started math now itself....OK
2007-01-18 06:54:56 · answer #5 · answered by yogesh gulhania 2 · 0⤊ 0⤋
infinite
2007-01-18 08:00:22 · answer #6 · answered by srinu710 4 · 0⤊ 0⤋