2007-01-17 21:12:08 · 6 answers · asked by chloelouise5754 1 in Science & Mathematics ➔ Biology
From the question, it is assumed that the parents do not have phenyl.....so the trait must be recessive.
Defining heterozygous means one recessive and one dominant allele. Pick a letter to represent your trait. Draw your Punnett square to see if the parents can actually produce a phenyl...kid. If they can, you will see 2 lower case alleles.
Hope that helps.
2007-01-17 21:18:27 · answer #1 · answered by teachbio 5 · 0⤊ 0⤋
Phenylketonuria is a recessive trait, so if both parents are heterozygous, it means that they are normal, but carry a hidden allele for the trait. It's a possibility 75% that the child will be normal.
2007-01-17 21:37:49 · answer #2 · answered by Barbara V 4 · 0⤊ 0⤋
the two hetro = Pp x Pp (P = no phenylketo ; p = phenylketo) Genetic... a million x PP (double dominant no phenylketo) 2 x Pp (2 hetro offspring) a million x pp (one double recessive phenyketo) (a million:2:a million) this could supply the phenotypes: 3 x established a million x phenylketo 3:a million i'm hoping this allows...
2016-12-16 07:25:08 · answer #3 · answered by ? 4 · 0⤊ 0⤋
You really should concentrate more when this is explained to you. I would suggest that you either open your text book covering this area of genetics or enter your question into a search engine and read and digest what appears.
2007-01-17 21:21:51 · answer #4 · answered by BARROWMAN 6 · 2⤊ 0⤋
If you can't think this through and research it do you think you may be taking the wrong subject?
2007-01-17 21:21:01 · answer #5 · answered by Em 6 · 1⤊ 1⤋
www.google.com will do your homework - I won't.
2007-01-17 21:15:31 · answer #6 · answered by C J 3 · 1⤊ 2⤋