From the question, it is assumed that the parents do not have phenyl.....so the trait must be recessive.
Defining heterozygous means one recessive and one dominant allele. Pick a letter to represent your trait. Draw your Punnett square to see if the parents can actually produce a phenyl...kid. If they can, you will see 2 lower case alleles.
Hope that helps.
2007-01-17 21:18:27
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answer #1
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answered by teachbio 5
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Phenylketonuria is a recessive trait, so if both parents are heterozygous, it means that they are normal, but carry a hidden allele for the trait. It's a possibility 75% that the child will be normal.
2007-01-17 21:37:49
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answer #2
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answered by Barbara V 4
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the two hetro = Pp x Pp (P = no phenylketo ; p = phenylketo) Genetic... a million x PP (double dominant no phenylketo) 2 x Pp (2 hetro offspring) a million x pp (one double recessive phenyketo) (a million:2:a million) this could supply the phenotypes: 3 x established a million x phenylketo 3:a million i'm hoping this allows...
2016-12-16 07:25:08
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answer #3
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answered by ? 4
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You really should concentrate more when this is explained to you. I would suggest that you either open your text book covering this area of genetics or enter your question into a search engine and read and digest what appears.
2007-01-17 21:21:51
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answer #4
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answered by BARROWMAN 6
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If you can't think this through and research it do you think you may be taking the wrong subject?
2007-01-17 21:21:01
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answer #5
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answered by Em 6
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www.google.com will do your homework - I won't.
2007-01-17 21:15:31
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answer #6
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answered by C J 3
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