CH4+Br2---->CH3Br+HBr
and...
Ba(CN)2+H2SO4---->BaSO4+HCN your my hero
2007-01-17 20:52:47 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
To balance any reaction:
List your atoms or polyatomic ions (like SO4...notice it stays together from reactant to product) in a column
Ex: C
H
Br
Now count up one of the atoms from the side with the highest number.....4 H on reactant side.
Now count H on product side....3+1 = 4 so H is balanced
Now count C on reactant side....1 C....1C on product side
Count Br on reactant side...2Br...2Br on product side
Do this same process for the second reaction, and for all others
2007-01-17 21:00:22 · answer #1 · answered by teachbio 5 · 0⤊ 0⤋
CH4 + Br2 ---> CH3Br +HBr (reaction one by one)
Ba(CN)2+H2SO4---> Ba SO4 + 2 HCN
2007-01-18 04:58:07 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
CH4+Br2------CH3Br+HBr
BY ALKYLATION IN PRESENCE OF U.V. LIGHT
FURTHER BY WURTZ SYNTHESIS
2CH3Br+2Na-----C2H6+2NaBr
Ba(CN)2+H2SO4-----BaSO4+2HCN
2007-01-18 08:02:02 · answer #3 · answered by amit m 1 · 0⤊ 0⤋